Question

Q-1 FIND THE LEAST NUMBER WHICH WHEN DIVIED BY 40,50 AND 60 LEAVES REMAINDER 5 IN EACH CASE ( L.C.M) plz solve it .......​

Answer 1

Answer:

hlo friend

Step-by-step explanation:

ur answer is here

=LCM(40,50,60)+5

=10×4×3×5= 600+5=605

605 is ur correct answer...✌✌

hope u like my answer.

plzz mark as brain list I have a great need of it plzz

follow me plzz

Answer 2

Taking the L.C.M of the three numbers:

L.C.M(40,50,60)=600

So, 600 is the lowest possible number which is divided by all the three numbers.

For 600 to leave remainder 5 each for 40,50,60 we add 5 to the LCM 600.

Ans) 600+5=605

Hence, On dividing 605 by any of the given numbers will leave 5 as the remainder.