Q:1 Find the product (√3-1) (2+√3)
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Answered by
1
(1+3√2)*(1-3√2)
So let 1 be ‘a’ and 3√2 be ‘b’.
Now (a+b)(a-b) => a^2-b^2
SUBSTITITING THE VALUES =>
(1+3√2)(1-3√2)
=>(1)^2-(3√2)^2
=>1-9(2)
=>1-18
=>-17.
Yes the product is a rational number => -17.
So -17 is the product of (1+3√2)(1-3√2) which isthe required answer.
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Answered by
1
Answer:
x+1/x = 4
Step-by-step explanation:
GIVEN:−
x = 2 + √3
1/x = 1/(2 + √3) * (2 - √3)/(2 - √3)
1/x = (2 - √3)/(4 - 3)
[ (a - b)(a + b) = (a² - b²) ]
1/x = (2 - √3)
now,
x + 1/x = (2 + √3) + (2 - √3)
x + 1/x = 2 + 2 + √3 - √3
x + 1/x = 4
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