Question

Q-1 Find the zeros of the
1. p(x) = 4x2 – 256

Answer 1

Step-by-step explanation:

p(x)=4x²-256 (by doing the square root of 256 we get 16)

p(x)=4x²-16²

p(x)=(4x-16)(4x+16) {a²-b²=(a-b)(a+b}

•x= 16/4=4

•x= -16/4= -4

☆So, zeroes of this equation are 4,-4

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