Question

Q. (1) Four years hence, the sum of ages of A and B will be 16 years more than the sum of the present age of B and
C. Four years ago, the sum of age of A and C is 32 years then find the present age of C?
1. 24 years
2. 20 years
3. 12 years
4. 16 years
5. 18 years​

Answer 1

The correct answer is 16 years.

According to the question:

Present age of A and C:

A + C = 40 ............(i)

After 4 years, sum of ages of A and B will be 16 years more than the sum of the present ages of B and C.

A + 4 + B + 4 = B + C + 16

A - C = 8 ............(ii)

On solving eq(i) and eq(ii).

2A = 48

A = 24

Then, the present age of C:

24 + C = 40

C = 16 Years

Answer 2

From the given question the correct option is 4.

i.e 16 years.

Let us find out the present age of C,

$A+4+B+4=16+B+C ...(1)$

$A$-4$+C-4=32 ...(2)$

so from the $eq (1) A-C=8$

and from  the $eq (2) A+C=40$

When subtracting (1) from (2)

we can get,

$2C=32$

So that the present age of C is 16 years.

Hence the option 4 is correct.