Math, asked by ojasagupta, 1 month ago

Q 1 - From a point 375 meters away from the foot of a tower, the top of the tower is
observed at an angle of elevation of 45°, then the height (in meters) of the tower is?​

Answers

Answered by muskanot7
3

 \tan(45)  =  \frac{base}{height}

 \frac{1}{ \sqrt{2} }  =   \frac{375}{height}

 height = 375 \sqrt{2}m

Hope this will help you❤️

Answered by Bhuvanashri
2

Answer:

The height of the tower is 375m .

Step-by-step explanation:

tan theta = Opposite side / adjacent side

tan 45° = x / 375

1 = x / 375

x = 375m

Diagram is attached as written copy in the form of an image.

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