Question

Q. 1. If 4 tan 0 = 3, evaluate
4 sin 8-cos8 +1
4 sino + cos8-1​

Answer 1

Explanation:

4 tan theta = 3 then,

tan theta = 3/4 = perpendicular/ base.

so,

P = 3 and B = 4

By Pythagoras theorem

H^2 = P^2+B^2

= 3^2+ 4^2.

= 9+16

H^2 = 25

H = 5.

now,

sin theta = p/h = 3/5.

cos theta = b/h = 4/5.

now again,

4sin8-cos8+1 = 4× 3/5 × 8 - 4/5×8+1

= 96/5 - 27/5

= 69/5.

4sin theta + cos8-1 = 4×3/5+ 4/5 ×8+1

= 12/5+32/5+1

= 49/5.