Question

Q.1) If one root of the quadratic polynomial 2x2 -3x + p is 3, find the other root. Also , find the value of p.

Answer 1

Here is your answer!!

Answer 2

Answer:

The value of p is -9

Two roots are 3 and $\frac{-3}{2}$

Step-by-step explanation:

Given that if one root of the quadratic polynomial $2x^2 -3x + p$ is 3,

we have to find the value of p.

As 3 is the root of quadratic polynomial therefore by remainder theorem

P(3)=0

$2(3)^2-3(3)+p=0$

$18-9+p=0$

$p=-9$

The polynomial becomes

$2x^2 -3x - 9$

$2x^2-6x+3x-9$

$2x(x-3)+3(x-3)$

$(2x+3)(x-3)$

Hence, two roots are 3 and $\frac{-3}{2}$