Question

Q.1 If the polynomials az3 + 4z2 + 3z -4 and z3 – 4z +a leave the same

remainder when divided by z-3, find the value of a.​

Answer 1

Answer:

a(x) ^3 +4(x)^2+3x-4

Now x=3 , put the value of x which is 3

f(3) = a(3) ^3 +4(3) ^2+3(3) -4... (i)

27a+36+9-4

27a+41=0....(ii)

(x) ^3-4(x)+a

3^3-4(3) +a

27-12+a

15+a=0....(iii)

As the remainder is same , we equate the eqs(ii) &(iii)

27a+41=15+a

26a=-26

a=-1

-1 is the answer... If iam not worng...

Hope the answer help you...