Question

Q.1 If x = 2, y = 3 evaluate the following -
a. 2x² + 2xy - 3y²

Q.2 Add the following :
a. 4p³ - 5p² - 8p + 7, 9p³ - 7p² + 2p - 12, -6p³ + 4p² + 5 ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Q.1 : (–7)

Q.2 : The sum is $\tt{{7p}^{3} - 8 {p}^{2} - 6p}$

Step-by-step explanation:

$\textsf{\underline{\underline{Question.1 - }}}$

Here -

• x = 2
• y = 3

Substitute the value of x and y in the expression 2x² + 2xy - 3y²

$\tt{\leadsto} \: 2{x}^{2} + 2xy - 3 {y}^{2} \\ \\ \tt{\leadsto} \:2 \times 2^{2} + (2 \times 2 \times 3) -3 \times{3}^{2} \\ \\ \tt{\leadsto} \: 2 \times 4 + 2(6) - 3 \times 9 \\ \\ \tt{\leadsto} \:8 + 12 - 27 \\ \\ \tt{\leadsto} \:20 - 27\\ \\ \tt{\leadsto} \: - 7$

Answer : –7

$\rule{300}{1.5}$

$\rule{300}{1.5}$

$\textsf{\underline{\underline{Question.2 -}}}$

Addition of : 4p³ - 5p² - 8p + 7, 9p³ - 7p² + 2p - 12 and -6p³ + 4p² + 5

$\tt{\leadsto} \:({\red{4 {p}^{3}} \orange{ - 5 {p}^{2}}\blue { - 8p} +\pink{ 7}) \red{ +(9{p}^{3}} \orange{ - 7 {p}^{2}} \blue{+ 2p} - \pink{12}) + (\red{-6 {p}^{3}} \orange{+ 4 {p}^{2}} +\pink{ 5})} \\ \\ \rm{\leadsto} \:\gray{Group \: like \: Terms} \\ \\ \tt{\leadsto} \: \red{{4p}^{3} + {9p}^{3} - { 6p}^{3}} \orange{- {5p}^{2} - {7p}^{2} + {4p}^{2}} \blue{- 8p + 2p} \pink{+ 7 - 12 + 5} \\ \\ \tt{\leadsto} \: \red{{13p}^{3} - { 6p }^{3}} - \orange{{12p}^{2} + {4p}^{2}} \blue{- 6p } \: \cancel{- 5 } \cancel{+ 5} \\ \\ \tt{\leadsto} \:\red{ {7p}^{3}}\orange{ - 8 {p}^{2}} \blue{ - 6p}$

Answer : $\boxed{\tt{7p}^{3} - 8 {p}^{2} - 6p}$

$\therefore$ The sum is $\tt{{7p}^{3} - 8 {p}^{2} - 6p}$