Chemistry, asked by suzanfelix06, 3 months ago

Q 1. In KOH [K=39, O=16, H=1] the percentage composition of(a)
Potassium is
a. 69.67
b. 69.64
c. 69.46

Answers

Answered by brightest98

1

Explanation:

the correct answer is b. 64.64

39+16+1=56

percentage of potassium is = 56×100/39

= 69.64

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