Question

Q.1 In the given figure AACD is an equilateral triangle. Find the value of AD.​

Answer 1

Step-by-step explanation:

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Given: AD=BD=AC ∠CAE=75°

In △ABD

AD=BD

∠ABD=∠BAD=x (Isosceles triangle property)

∠ADC=∠ABD+∠BAD=2x (Exterior angle property)

In △ACD

AD=AC

hence, ∠ADC=∠ACD=2x (Isosceles triangle property)

Now, ∠CAE+∠BAC=180 (Linear pair)

75+∠BAC=180

∠BAC=105°

Sum of angles of triangle ABC = 180

∠BAC+∠ABC+∠ACB=180

105+x+2x=180

3x=75

x=25

Thus, ∠ACB=∠ACD=2x=2×25=50°

Hope it helpful...☃️⚡️