Question

Q.1 In the given figure ZABC = 25° then ZAOC =
C
25°
B
(A) 135°
(B) 145°
(C) 165°
10) 155°
​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

In the given figure ∠ABC = 25° then ∠AOC =

(A) 135°

(B) 145°

(C) 165°

(D) 155°

EVALUATION

Here in the figure two tangents at A & C meets at the point B

We know that at the point of Tangency, Tangent to a circle is always perpendicular to the radius.

So OC is perpendicular to BC & OA is perpendicular to AB

∴ ∠ ABC + ∠ AOC = 360° - ( 90° + 90° )

∴ ∠ ABC + ∠ AOC = 180°

∴ ∠ AOC = 180° - 25° = 155°

FINAL ANSWER

Hence the correct option is

(D) 155°

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