Question

Q. 1. In triangle ABC, AD IBC, prove
that : AB2+CD= BD? + AC2.​

Answer 1

Answer:

Refer to the attachment

Answer 2

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In right ∆ADC

by Pythagoras Theorem,

AC² = AD² + CD² _____________(i)

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In right ∆ADB,

by Pythagoras Theorem,

AB² = AD²+ BD² ______________(ii)

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Subtracting (i) from (ii), we get

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AB² - AC² = BD² - CD²

AB² + CD² = BD² + AC²

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Hence Proved.