Q #1 - Observe the following velocity-time graph and answer the related question: what is the rise in velocity from 11 to 12
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Explanation:
(a)Since velocity is not changing, acceleration is equal to zero.
(b) Reading the graph, velocity=20ms
−1
(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m
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