Question

Q.1 of 60
A current I = 20 sin (100nt)A i
passed in the first coil, which
induces a maximum emf of
10nV in the second coil. The
mutual inductance for the pair
of coils is
You m
10 mH​

Answer 1

Explanation:

I=10sin(100πt)

⇒dtdI=10×100πcos100 nt⇒dtdI∣∣∣∣∣mass=1000π

we know that ϕ=mI;m= mutual inductance

⇒dtdϕ=mdtdI

∣emt∣=∣∣∣∣∣dtdϕ∣∣∣∣∣⇒e∣∣∣∣max=mdtdI∣∣∣∣∣max

Put e=Sπ & value of dtdI∣∣∣∣∣max

We get m=