Q-1 Radius of a circle 21 cm and of the sector is 60. Find--
(a) Length of the arc
(b) Area of the minor sector
(c) Area of the segment.
(d) Area of the major segment.
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Step-by-step explanation:
Radius (r) of circle = 21 cm
Angle subtended by the given arc = 60°
Length of an arc of a sector of angle θ =
Length of arc ACB =
= 22 cm
Area of sector OACB =
In ΔOAB,
∠OAB = ∠OBA (As OA = OB)
∠OAB + ∠AOB + ∠OBA = 180°
2∠OAB + 60° = 180°
∠OAB = 60°
∴ ΔOAB is an equilateral triangle.
Area of ΔOAB =
Area of segment ACB = Area of sector OACB − Area of ΔOAB
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