Math, asked by nikiviki031, 8 months ago

Q-1 Radius of a circle 21 cm and of the sector is 60. Find--
(a) Length of the arc
(b) Area of the minor sector
(c) Area of the segment.
(d) Area of the major segment.​

Answers

Answered by singhbn972
0

Step-by-step explanation:

Radius (r) of circle = 21 cm

Angle subtended by the given arc = 60°

Length of an arc of a sector of angle θ =

Length of arc ACB =

= 22 cm

Area of sector OACB =

In ΔOAB,

∠OAB = ∠OBA (As OA = OB)

∠OAB + ∠AOB + ∠OBA = 180°

2∠OAB + 60° = 180°

∠OAB = 60°

∴ ΔOAB is an equilateral triangle.

Area of ΔOAB =

Area of segment ACB = Area of sector OACB − Area of ΔOAB

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Answered by tennetiraj86
0

Answer:

answers for the given problem are given

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