Math, asked by swayashmahajan1, 7 months ago

Q.1) Simplify
sin 67.cos 23 + cos 67.sin 23
sec 43.cosec 47 -tan 43.cot 47 -1​

Answers

Answered by nandika32
0

Answer:

the answer is in the image

sec^2x-tan^2x=1

Attachments:
Answered by Amit137950
0

Answer:

1

Step-by-step explanation:

sin67.cos23+cos67.sin23+sec43.cosec47-tan42.cot47-1

=sin67.cos(90-67)+cos 67.sin(90-67)+1/cos43.1/sin(90-43)-tan43.cot(90-43)-1

=(sin²67+cos²67)+1/cos²43-tan²43-1

=1-1+sec²43-tan²43

=0+1

=1. (ans)

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