Question

Q.1) Solve for x :
√6x+7 - (2x-7) =0
plz solve this ...​

Answer 1

$\: \: \: \: \sqrt{6}x + 7 - 2x + 7 = 0 \\ = > ( \sqrt{6} - 2)x + 14 = 0 \\ = > x = \frac{ - 14}{( \sqrt{6} - 2) }$

Answer 2

Answer:

Sqrt (6x +7) - (2x - 7 ) = 0

sqrt ( 6x + 7 ) = ( 2x - 7 )

Squreing bothsides

( sqrt ( 6x + 7 ))^2 = ( 2x - 7 )^2

6x + 7 = 4x^2 -28x +49

0 = 4x^2 -28x -6x +49 - 7

4x^2 -34x +42 = 0

Divide each term with 2

2x^2 - 17x +21 = 0

2x^2 - 14x - 3x +21 = 0

2x ( x - 7 ) - 3( x - 7 ) = 0

( x - 7 ) ( 2x - 3 ) = 0

x - 7 = 0 or 2x - 3 = 0

x = 7 or 2x = 3

x = 7 or x = 3/2

I hope this will help you .

Step-by-step explanation:please follow and mark as brainliest