Q.1 Solve the following 5x4=20
1. Subtract 5xy – 4x2
+ 3y2
from 3x2
– 5y2
– 4xy .
2. Simplify : ( 14 -7) x { 8 + ( 3+ 7) – 1}
3. The sum of two integers is 48 .If one of the integers is -24 , find the
other.
4. Find the HCF and the LCM of 1152 and 1664 .
5. Find the greatest number which exactly divides 81 and 117.
CLASS - 6
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Answers
Step-by-step explanation:
1)3x^2-5y^2-4xy-(5xy-4x^2+3y^2)=7x^2-8y^2-9xy
2)7*17=119
3)x+-24=48
x=48+24=72x
5)9
Answer:
Step-by-step explanation:
1.3x2– 5y2– 4xy - (5xy – 4x2+ 3y2)
=3x2– 5y2– 4xy - 5xy + 4x2 - 3y2
= 3x2+ 4x2 – 5y2- 3y2– 4xy - 5xy
= 7x2 - 8y2– 9xy
2.( 14 - 7 ) × [ 8 + ( 3 + 7 - 1 ) ]
=7 × [ 8 + 9 ]
=7 × 17
=119
3.Let the integers be X and Y respectively,
then, X + Y = 48
=> -24 + Y = 48
:. Y = 48 + 24 = 72
4.Prime factorization of 1,152 =>
1,152 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
Prime factorization of 1,664 =>
1,664 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 13
LCM = 2^7 × 3^2 × 13 = 14,976
HCF = 2^7 = 128
LCM × HCF = A × B
=> 14,976 × 128 = 1,152 × 1,664
=> 19,16,928 = 19,16,928
Hence, verified.
5.Find Prime Factorization of 81 and 117
i.e. 81 = 3 × 3 × 3 × 3
117 = 3 × 3 × 13
The common factors are 3 × 3 =9
(HFC)Highest number which exactly divides 81 and 117 is 9.
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