Q.1) The area of a square is 144cm3 find its length and perimeter.
Q.2) The area of a rectangle is 96cm3 its length is 8cm find its perimeter.
Q.3) A square has a perimeter of 44m find its area.
Q.4) A rectangle has an area of 48m3 sketch 3 possible rectangles with different perimeters.
Answers
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Answer:
question number 1)
Given:- (A) Area of a square=144 square cm.
Find:- Perimeter of square (P)=?
Solution:-
Area (A)=length×width
Because all sides are of same size of a square
So side (S) of a square= √144
S(one side of square)=12 cm
Now perimeter (P)= 4×s
P= 4×12
P(Perimeter of square)=48 cm. Answer
question number 2)
We know Area of rectangle = length × width
Length of rectangle = 8 cm.
Width of rectangle is w cm.
Area of rectangle = 96 cm^2
Area of rectangle = length × width
96 cm^2 = 8 cm × w cm.
8w = 96
w = 96/8
w = 12 cm.
The width of rectangle is 12cm.
Now Perimeter of rectangle
Perimeter = 2 (length + width)
Perimeter = 2 ( 8 cm. + 12 cm)
Perimeter = 2 ( 20 cm)
Perimeter = 40 cm.
Answer : the perimeter of rectangle is 40 cm.
question number 3)
Given, Perimeter of square =44 cm
We know perimeter of square =4a
where
′
a is side of square
4a=44cm⇒[a=11cm]
Area of square = (a) ^2=(11) ^2
Area = 121 cm square
Hence, area of square is 121cm ^2
question number 4)
rectangles can have the same perimeter but different area by building rectangles and organizing information in a chart.
hope will be helpful ☺️