Math, asked by mirgalriddhi, 3 months ago

Q.1) The equation 24x2+25x−47÷ax-2=−8x−3-53÷ax-2 is true for all values of x≠2a, where a is a constant.

What is the value of a?

A) -16
B) -3
C) 3
D) 16​

Answers

Answered by rajveersen945
1

Answer:

-3

Step-by-step explanation:

Given,

ax−2

24x

2

+25x−47

=−8x−3−

ax−2

53

ax−2

24x

2

+25x−47

=

ax−2

(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=(−8x−3)(ax−2)−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax+6−53

⇒24x

2

+25x−47=−8ax

2

+16x−3ax−47

⇒24x

2

+25x=−8ax

2

+(16−3a)x

⇒24=−8a

⇒a=−3

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