Q.1) The equation 24x2+25x−47÷ax-2=−8x−3-53÷ax-2 is true for all values of x≠2a, where a is a constant.
What is the value of a?
A) -16
B) -3
C) 3
D) 16
Answers
Answered by
1
Answer:
-3
Step-by-step explanation:
Given,
ax−2
24x
2
+25x−47
=−8x−3−
ax−2
53
⇒
ax−2
24x
2
+25x−47
=
ax−2
(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=(−8x−3)(ax−2)−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax+6−53
⇒24x
2
+25x−47=−8ax
2
+16x−3ax−47
⇒24x
2
+25x=−8ax
2
+(16−3a)x
⇒24=−8a
⇒a=−3
Similar questions