Question

Q.1: The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower.​

Answer 1

Answer:

In △ABD,

tan60o=BDAB

3=xh

∴   x=3h                ------- ( 1 )

Now in △ABC,

tan30o=BCAB

⇒  31=x+40h

⇒  x+40=3h

∴  3h+40=3h          [  From equation ( 1 ) ]

⇒  h+403=3h

⇒  2h=403

∴  h=203m

∴  The height of a tower is 203m.

Step-by-step explanation:

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Answer 2

Answer:

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