Q.1. The width of a rectangle is 4cm. If the perimeter must be at least 56 cm. Find the smallest possible length it can have.
Answers
Answered by
3
2(l+b) = 56
2(l+4) = 56
2l + 8 = 56
2l = 48
l = 24cm
2(l+4) = 56
2l + 8 = 56
2l = 48
l = 24cm
Answered by
4
Hey.
Here is the answer.
b = 4 cm
let l be the least possible length
least perimeter = 56 cm
so, 2×( l + b ) = 56
so, 2×( l + 4 ) = 56
or, 2 l = 56-8 = 48
so, l = 24 cm
Thanks
Here is the answer.
b = 4 cm
let l be the least possible length
least perimeter = 56 cm
so, 2×( l + b ) = 56
so, 2×( l + 4 ) = 56
or, 2 l = 56-8 = 48
so, l = 24 cm
Thanks
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