Math, asked by nandini5410, 7 months ago

Q.1 Two cross roads, each of width 5 m, run at right angles through the centre of a
rectangular pārk of length 70 m and breadth 45 m parallel to its sides. Find the
area of the roads. Also, find the cost of constructing the roads at the rate of Rs
105 per m.​

Answers

Answered by anshumanmohanty50890
2

Answer:

Solution:-

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70*5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45*5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5

 

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550*105

= Rs. 57750

hope it is helpful to you

Answered by Anonymous
0

Answer:

➥57,750.

Step-by-step explanation:

➥see in attachment

➥hope its helps you .

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