Question

Q 1 . “Two years later, the age of father will be 8 years more than three times the age of his son”. Taking present ages (in years) of father and son as and respectively (i) Find the linear equation of the above condition. (ii) Find the present age of the father when the son’s present age is 10 years. (i) (ii) (A) − 3 − 12 = 0 56 years (B) + 3 − 14 = 0 56 years (C) − 3 − 12 = 0 42 years (D) − 3 − 14 = 0 56 years​

Answer 1

Answer:

Given, father’s age is 3 times as his son’s age.

Let the present age of father be ‘a’ and the present age of his son is ‘b’

So, by the given condition, a = 3b ……(1)

Also given, after twelve years, Father’s age is twice as his son’s age.

Therefore, (a + 12) = 2(b + 12)

⇒ a + 12 = 2b + 24

⇒ a = 2b + 12 ……(2)

On substituting eq(1) in eq(2), we get,

⇒ 3b = 2b + 12

⇒ b = 12

On putting b = 12 in eq(1), we get

a = 2(12) + 12 = 36

Hence, the present age of Father is 36 years and the present age of son is 12 years.