Physics, asked by atharvpatidar47, 6 months ago

Q.1
Work done by constant Force
A block of mass M=9 kg is moving with uniform velocity of 2 m/s on a rough horizontal surface under
the action of constant force F. The force acts at an angle 37° to the horizontal. Find work done by the
force F during an interval of 4 s of motion.

(A) 400 J
(B) 300 J
(C) 320 J
(D) 100 J

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Answers

Answered by MrJalajjjjj
0

Explanation:

on a rough horizontal surface under

the action of constant force F. The force acts at an angle 37° to the horizontal. Find work done by the

force F during an interval of 4 s of motion.

(A) 400 J

(B) 300 J

(C) 320 J

(D) 100 J

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