Question

Q-10 A ball thrown vertically upwards with a speed of
19.6 ms -1 from the top of a tower returns to
the earth in 6 seconds. Find the height of the
tower. (g = 9.8ms-2)​

Answer 1

Answer:

h=294 meters

Explanation:

u=19.6m/s

g= -9.8ms^-2

t=6sec

By using the second equation of motion,

h=ut+1/2 gt^2

h=19.6×6+1/2×(-9.8)×6^2

h=117.6+176.4

h=294m

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