Question

Q. 10. A block of 8 kg is moving with 4 m/s on a frictionless surface. This block compresses a spring and comes to rest. If spring constant is 2x10^4 N/m then find the compression in the spring.
Please remember that it is 8kg not 9kg.
So, please give the correct answer. ​

Answer 1

Answer:

hloo mate..

here's your answer...

Explanation:

Given, mass= 8kg, v= 4m/s,

$k = 2 \times {10}^{4} = 20000$

so,

$\frac{1}{2} k {x}^{2} = \frac{1}{2} m {v}^{2}$

$\frac{1}{2} \times 2 \times {10}^{4} \times {x}^{2} = \frac{1}{2} \times 8 \times 16$

${10}^{4} {x}^{2} = 64$

${x}^{2} = 64 \times {10}^{ - 4}$

$x = \sqrt{64 \times {10}^{ - 4} }$

solving this,we get

$x = 8 \times {10}^{ - 2}$

hope it helps..

and also hope that u will mark it brainliest....

Answer 2

Answer:

Hey mansi,,,,

Answer:-

8×11¯²......

Please mark it as a brainliest and please follow me