Q.10 A body is at a height equal to the radius of the earth from surface of
earth.With what velocity should it be thrown so that it goes out of
the gravitational field of the earth ?
Given mass of earth = 6.0 x 1024 kg., radius of earth = 6.4 x 106 m
and G = 6.67 x 10-11 Nm2 kg-2
2.5
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Answer:
According to Universal law of gravitation, the force of attraction between 2 bodies is:-
F = (G m1m2)/r2
Where m1m2 = the masses of the two bodies,
r = distance between them
G = gravitational Constant
When the distance is reduced to half i.e. r’ = (1/2) r then,
F’ = (G m1m2)/r2
= (G m1m2)/(r/2)2
= (4 G m1m2)/ (r2) = 4F
Therefore when the distance between the objects is reduced to half, then the force of gravitation increases by four times the original force.
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