Question

Q 10 and 11 plzz its urgent tomorrow my final exam​

Answer 1

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10. given mass 16 g
molecular mass of sulphur 32 g

no. of molecules =given mass/ molecular mass× avagadro's no.

=16 ÷32 ×6.022 10 ^23
=3.011 ×10^ 23 molecules

11. see attachment...


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