Question

Q 10 c plz help by mentioning the theorem used here​

Answer 1

Answer:

through Hypotenuse theorem

in triangle ACD = CD = 60°

AC

= BASE = Cosec 60°

PERP

= CD = 1/2 *10= 5

CD= x = 5m

now for y =

PERP = Y°

HYP

= 5. = Sin y°

5√2

= 1. = sin30

√2

y = 30°