Math, asked by aashathatiwari009988, 4 months ago

Q-10 construct a square, each of whose diagonals measure 5.8 cm​

Answers

Answered by ParikhAyushi
20

Answer:

Steps of construction :

Step 1: draw AC line which is equal to 5.8 cm..

Step 2: draw the perpendicular bisector XY of AC, meeting it at O.

Step 3: from O:OB=1/2(5.8)cm=2.9 CN OD equal 1/2(5.8)=2.9 cm

Step 4: join AB BC CD and DA

ABCD is required square...

Step-by-step explanation:

Hope its help ☺️

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Answered by asahilthakur
2

Step-by-step explanation:

1. Construct the line segment AC of length 5.8 cm.

2. The diagonals of a square bisect each other at right angles.

3. Measure 2.9 cm from A and name the point of 2.9 cm as O.

4. With center as O, construct an arc and cut two smaller arcs which represent 60° and 120° respectively.

5. Bisect 60° and 120° to obtain 90°.

6. From the arc of 90° construct the line segment BD such that it intersects the point O.

7. Join AB, BC, CD and DA.

8. ABCD is the required square.

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