Question

Q.10. If cot 0 = 3/4 and π <O<3π/4 find the value of
4 coseco + 5 cose.​

Answer 1

Answer:

-8 is the correct answer

Step-by-step explanation:

Given that cot∅ = 3/4

As cot∅ is positive,∅ would lie in third quadrant

From,cosec²∅ - cot²∅=1

→cosec²∅=1 + cot²∅

→cosec²∅ = 1+(3/4)²

→cosec²∅ = 25/16

→cosec∅ = ±5/4

→cosec∅ = -5/4

Also,

sin∅ = -4/5

We know that,

cos∅ = sin∅cot∅

→cos∅ = (-4/5)(3/4)

→cos∅ = -3/5

Now,

4cosec∅ + 5cos∅

= 4(-5/4) + 5(-3/5)

= -5 -3

= -8

Answer 2

cot = base /perpendicular

cot =3/4

base=3

perpendicular =4

4coses=4×1/4=1

5cos =5×3=15

4cosec+5cos=16