Q.10. If n{A-B) = 12, n(B - A)
=16 and n(A intersection B) = 5
then n(A unionB) will be
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From the question it is given that,
n(A−B)=12
n(B−A)=16
n(A∩B)=5
(i) n(A)
We know that, n(A)=n(A−B)+n(A∩B)
=12+5
=17
(ii) n(B)
We know that, n(B)=n(B−A)+n(A∩B)
n(B)
=16+5
=21
(iii) n(A∪B)
We know that, n(A∪B)=n(A)+n(B)−n(A∩B)
=17+21−5
=38−5
n(A∪B)=33
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