Q#10 If Vectors |A|=|B|= 1 and A.B = 1/2 then |A-B| = ?
(a) 2
(b) 5
(c) 0
(d) 1
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Given,
|A| =|B| = 1
A.B = 1/2
we know,
A.B = ABcos∅ = 1/2
AB = 1 {give)
cos∅ = 1/2
so, ∅ = 60°
Now,
|A-B| = √(A²+(-B)²-2ABcos∅)
=>√(1+1-2×1/2)
=>√(2-1) = 1
The correct option is (d)1
Cheers!
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