Q.10 If x +1/x
= 8, find the value of x² +1/x2
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x+ 1/x = 8
Squaring both sides
(x+1/x)^2 = (8)^2
By (a+b)^2 = a^2 + b^2 + 2ab
x^2 + 1/x^2 + 2 = 64
=> x^2 + 1/x^2 = 64-2 = 62
Squaring both sides
(x+1/x)^2 = (8)^2
By (a+b)^2 = a^2 + b^2 + 2ab
x^2 + 1/x^2 + 2 = 64
=> x^2 + 1/x^2 = 64-2 = 62
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