Question

Q.10 In figure, AD is the median of triangle ABC. E is the mid-point of AD and F is the mid-point

od AE. Prove that ar (∆ ABF) = 1/

8

ar (ABC).​

Answer 1

hey mate

here is your answer

in ∆ABC

AD is median

ar(∆ ABD) = ar(∆ACD)

ar(∆ABD)= 1/2 ar(∆ABC)........1

in ∆ABD

BE is median

ar(∆BED)=ar(∆ABE)

ar(∆ABE)= 1/2ar(∆ABD)

from 1

ar(∆ABE)= 1/4ar(∆ABC )..........2

in ∆ABE

BF is median

ar(∆ABF) =ar(∆BFE)

ar(∆ABF)=1/2ar(∆ABE)=1/4ar(∆ABD)=1/8ar(∆ABC)

ar(∆ABF)= 1/8 ar(∆ABC)

.....hence proved

ноꤐꤢ ᰌт нᰀ꤈ꤐꤔ ꤓ :)

#thevamp