Question

Q.10 In the figure, ZZABC = 40° then find LZADC
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Answer 1

${\huge{\bold{\underline{Question:-}}}}$

In the given figure, ABCD is a cyclic quadrilateral such that ∠ADB= 40° and ∠DCA = 70°, then find the measure of ∠DAB .

${\huge{\bold{\underline{Answer:-}}}}$

➪ ∠BCA = ∠ADB = 40° [angles in same segment of a circle are equal]

Now, ∠BCD = 70° + 40° = 110°

∠DAB + ∠BCD = 180°

∠DAB = 180° - 110°

⇒ ∠DAB = 70°