Question

Q-10. Solve if possible ( x2 + 1 )2 - x2 = 0
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Answer 1

Step-by-step explanation:

$(x {}^{2} + 1)2 - x {}^{2} = 0 \\ 2x { }^{2} + 2 - x {}^{2} = 0 \\ x {}^{2} +2 = 0 \\ x (x + 2) = 0$

Therefore x can be 0 or - 2

Hope it helps

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