Question

Q.10 the average translational kinetic energy of a molecule of an ideal gas at absolute temperature t is

Answer 1

Answer:

E = 3kT/2

T = (37+273)K = 310K

E = 1.5*310*1.38*10^(-23) J

E = 641.7*10^(-23) J

E = 0.0401 eV

Answer 2

Understanding the concept behind :

• E = 3kT/2 [ Formula needed ]

• T = (37+273)K = 310K

• E = 1.5 × 310 × 1.38 × 10^(-23) J

• E = 641.7 × 10^(-23) J

• E = 0.0401 eV

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