Math, asked by brindaMS, 5 months ago

Q. 10. The length, breadth and height of a room are 8 m
50 cm, 6 m 25 cm and 4 m 75 cm respectively. Find
the length of the longest rod that can measure the
dimensions of the room exactly



(In this question we should find HCF)
can anyone say why we should find hcf ​

Answers

Answered by Anonymous
6

Step-by-step explanation:

The given dimensions are 825cm, 675cm & 450cm.

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from above

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2 =75

The given dimensions are 825cm, 675cm & 450cm.Now to find the length of room we need a common factor of 825,675,450Using Prime factorization:825=3×5 2 ×11675=3 2 ×5 2 450=2×3 2 ×5 2 Now from aboveHCF=3×5 2 =75∴ The length of longest rod to measure the length of room is 75cm.

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