Q.10 The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer
than the smaller side and the third side is 6 cm less than twice the smaller side. Find
the area of the triangle.
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Let the smallest side of the triangle be x cm long
So, second side =(x+4)cm
and third side =(2x−6)cm
Given, perimeter =50cm
Therefore, x+(x+4)+(2x−6)=50
⇒4x=52
⇒x=13cm
So, first side of the triangle is 13cm, second side be 17cm and third side is 20cm.
Now, semi-perimeter of the triangle =213+17+20=25cm
Therefore, area of Δ=s(s−a)(s−b)(s−c)
=25(25−13)(25−17)(25−20)
=25×12×8×5
= 2030cm2
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