Question

Q.10 Young modulus
of elasticity of brass
is
1011 N/m? On pressing the rod of length 0.1 m. and cross-sectional are 1 cm?
made from brass with a force of 10 kg along its length, the increase in its energy
will be​

Answer 1

Explanation:

Increase in energy

ΔE=

2

1

× stress × strain × volume

ΔE=

2

1

×

A

F

×

A×Y

F

×(A×L)

ΔE=

2

1

×

A

F

×

Y

FL

=

2

1

×

10

−4

10

×

10

11

10×0.1

ΔE=5×10

−7

J.