Question

Q. 11. A stone is dropped into a well, 44.1 metres deep. The sound of the splash is herd
3.13 seconds after the stone is dropped. Find the velocity of sound in air.
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Answer 1

Answer:

Time taken by the stone to reach the water surface can be calculated using the equation of motion s = ut + ½ gt2 Here u = 0, s = 44.1 m , g = 9.8 m/s2 So t = (2x44.1/9.8)½ = 3 s Therefore time taken by sound to travel this distance = 3.13 - 3 = 0.13 s Speed of sound in air = distance covered/Time = 44.1 m/ (0.13 s) = 339.23 m/s