Question

Q.11) A stone of mass one kilogram is tied to the end of string of length 5m & whirled in a vertical circle. What will be the minimum speed required at the lowest position to complete the circle?
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Answer 1

GIVEN : Length of the string is 5m

TO FIND : Minimum velocity at the lowest position

SOLUTION :

For completing a vertical circular motion the minimum velocity required at the bottom is given as $\sqrt{5rg}$ where r= radius and g = acceleration due to gravity

  so, the velocity at the bottom of the string  = $\sqrt{5*5*9.8}$

                                                   = $\sqrt{245}$

                                                   = 15.65 m/sec