Q:11 According to given question, write the linear equation
(a) y = x+20 (b) y = 5x + 20 (c) x=y=20 (d) x=y-20
Q:12 If she distributed 145 chocolates then how many children are there in the
orphanage
(a) 20 (b) 15 (C) 25 (d) 30
0:13 If the number of children is 18, then find the number of distributed cho
(a) 90 (b) 100 (C) 110 (d) 120
Answers
SOLUTION
GIVEN
Charity is the act of giving help tp those in meed it. It is a humatarian act. So in this order, Radha distributed chocolates in an orphanage, on her birthday, she gave 5 chocolates to each child and 20 chocolates to adults
Taking number of children as x and total chocolates distributed are y.
i) Write a linear equation, according to given question.
a) y=20x+5
b) x=20y+5
c) y=5x+20
d) y=20x+10
ii) If she distributed 145 chocolates, then how many children are there in the orphanage
a) 20
b) 25
c) 30
d) 35
iii) If she distributed 205 chocolates, then how many children are there in the orphanage?
a) 36
b) 37
c) 39
d) 41
iv) If there are 20 children, then find the required number of chocolates.
a) 70
b) 90
c) 120
d) 75
EVALUATION
Here it is given that Charity is the act of giving help tp those in meed it. It is a humatarian act. So in this order, Radha distributed chocolates in an orphanage, on her birthday, she gave 5 chocolates to each child and 20 chocolates to adults
(i) Now number of children as x and total chocolates distributed are y.
So the required linear equation is y = 5x + 20
Hence the linear equation, according to given question.
c) y = 5x + 20
(ii) Now she distributed 145 chocolates
So y = 145
y = 5x + 20 gives
145 = 5x + 20
If she distributed 145 chocolates, then the number of children in the orphanage
b) 25
(iii) Now she distributed 205 chocolates
So y = 205
y = 5x + 20 gives
205 = 5x + 20
If she distributed 205 chocolates, then the number of children in the orphanage
b) 37
(iv) Now If there are 20 children
Then x = 20
If there are 20 children, then the required number of chocolates.
c) 120
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