Science, asked by rimyshaju, 5 months ago

Q. 11. Calculate the number of aluminium ions present in 0.051 g of aluminium
oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic
mass of Al = 27 u.]

Answers

Answered by nihalbisht08
4

Answer:

1 mole of Al  

O  

2

​  

3

​  

=2×27+3×16

                    =102g

Moles of Al  

2

​  

O  

3

​  

=  

102

0.051

​  

=5×10  

−4

 moles

1 mole contains 6.02×10  

23

molecules

∴5×10  

−4

g of Al  

2

​  

O  

3

​  

 contains = 5×10  

−4

×6.02×10  

23

=3.011×10  

20

 molecule  

no. of Al  

3+

 ions in 1 molecules of Al  

2

​  

O  

3

​  

 is 2.

∴ No. of aluminium ions will be:-

2×3.011×10  

20

=6.022×10  

20

.

Explanation:

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