Question

Q.11: Find the nature of the roots of the equation
3x2 – 2x +
0. If real roots exist, find them.
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Answer 1

Answer:

Step-by-step explanation:

Here, equation is , 3x2−2x+13=0

Comparing it with, ax2+bx+c=0

a=3,b=−2 and c=13

So, discriminant,(d)=b2−4ac−−−−−−−√

d=(−2)2−4(3)(13)−−−−−−−−−−−−−−−√=0

We know, if d≥0, roots are real and if d<0, roots are unreal. Here, as d=0, roots are real and equal. Now, roots are=−b±d−−√2a=−b2a=13 So, roots are (13,13)

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