Question

Q.11 State the laws of refraction. A convex lens has focal length of 2cm find its
magnifying power if image is formed at DDV.​

Answer 1

Answer:

Focal length of the objective lens (f1) = 2.0 cm

Focal length of the eyepiece (f2) = 6.25 cm

Distance between the objective lens and the eyepiece (d)= 15 cm

(a) Least distance of distinct vision, (d1) = 25 cm

Therefore, Image distance for the eyepiece (v2) = – 25 cm

Object distance for the eyepiece = u2

According to the lens formula,

1/ v2 - 1/u2 = 1/ f2

1/u2 = 1/ v2 -1/ f2 = 1/-25 - 1/6.25 = -1-4/ 25 = -5/25

u2 = -5 cm

Image distance for the objective lens, (v1) =- d + u2 = 15-5 = 10 cm

Object distance for the objective lens = u2

According to the lens formula,

1/ v1 - 1/u1 = 1/f1

1/u1 = 1/ v1 - 1/f1

= 1/10 - 1/2 = 1-5/10 = -4/10

u1 = -2.5 cm

Magnitude of the object distance (u1) = 2.5 cm

The magnifying power of a compound microscope

m = v1/ u1 (1 + d1/f2)

= 10/2.5 (1 + 25/6.25)

= 4 (1 +4) = 20

Hence, the magnifying power of the microscope is 20.

Laws of refraction state that: The incident ray, reflected ray and the normal, to the interface of any two given mediums; all lie in the same plane. The ratio of the sine of the angle of incidence and sine of the angle of refraction is constant.

Explanation:

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