Question

Q. 11 Two bodies P and Q collide with
each other, P exerts a force of 10 N
on Q towards east direction. The
force exerted by Q on Pis -
10 N towards the north as per
Newton's III Law
EA
12-1
10 N towards the west as per
Newton's Il Law
10 N towards the west as per
Newton's III Law
10 N towards the south as per
Newton's I Law

Answer 1

Answer:

hii I think that it helps you

Explanation:

Momentum carried by 1 bullet=P

1bullet

=m

lb

×v

=5×10

−3

×600

⇒P

1b

=3 kg.m/s

∵ Total momentum carried by bullets in 1 min:

P

1min

=P

lb

×100=300kg. m/s

∴ By Newton's second law: <

F

ˉ

>=Average force needed to hold the gun

T- Time taken for the momentum change.

<

F

ˉ

>=

T

P

ˉ

1min

=

60

300kgm/s

⇒<

F

ˉ

>=5N